Could the Patriots be a landing spot for Richard Sherman?
Four-time All-Pro cornerback Richard Sherman does not expect to return to the Seattle Seahawks, and has already told some of his teammates goodbye, according to an NFL.com report.
That text message got my heart hurting … damn 25 was my Dawg #WhatsNext
— jeremy lane (@StayingInMyLane) March 7, 2018
“He reached out to people very close to him this morning and late last night and told them that he believed he was getting released from Seattle — that he would simply not be on the team,” NFL Network’s Ian Rapoport reported Wednesday. “Then he went into a phone call with John Schneider, the general manager, and Pete Carroll, the coach, and they discussed his fate.”
From @NFLTotalAccess: The #Seahawks are now expected to shop CB Richard Sherman… with him no longer slated to be on the team. His injury status doesn’t help. pic.twitter.com/7aJ4zLfQTU
— Ian Rapoport (@RapSheet) March 8, 2018
Sherman, who tore his right Achilles last season, played just nine games in 2017. He underwent surgery for his right Achilles in November. Carroll also recently revealed at the NFL Scouting Combine that Sherman underwent minor surgery on his left Achilles as well. He is still expected to be able to participate in training camp.
“It’s a bit of a setback for a couple weeks because he’s in the boot on the other leg,” Carroll told reporters. “But he is not slowing down. He’s working like crazy. He’s having a fantastic offseason. His mentality is good. He’s competing like crazy.”
The Seahawks could trade or cut Sherman, who is due $11 million in 2018. According to Rapoport, the team is expected to “explore trade options” for the 29-year-old.
The Patriots have been linked to Sherman, and reportedly called the Seahawks about his availability last season. Their interest dwindled, however, after they signed then-free agent Stephon Gilmore and retained cornerback Malcolm Butler.
The Boston Herald‘s Jeff Howe reported Sherman was “receptive to the idea of joining the Patriots” last offseason, and according to Howe, that is still the case.
